A) -6 units
B) 13 units
C) 1 units
D) 5 units
Correct Answer: B
Solution :
| Here, \[{{x}_{1}}=-6,\,{{y}_{1}}=7,\,{{x}_{2}}=-1\] and \[{{y}_{2}}=-5\] |
| \[\therefore\] Distance between two points, |
| \[PQ=\sqrt{{{\left( {{x}_{2}}-{{x}_{1}} \right)}^{2}}+{{\left( {{y}_{2}}-{{y}_{1}} \right)}^{2}}}\] |
| [by distance formula] |
| \[=\sqrt{{{\left( -1+6 \right)}^{2}}+{{\left( -5-7 \right)}^{2}}}\] |
| \[=\sqrt{{{\left( 5 \right)}^{2}}+{{\left( -12 \right)}^{2}}}\] |
| \[=\sqrt{25+144}=\sqrt{169}=13\] units |
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