10th Class Mathematics Coordinate Geometry Question Bank MCQs - Coordinate Geometry

  • question_answer
    If \[P\left( \frac{a}{3},4 \right)\]is the mid-point of the line segment joining the points \[Q\left( -6,\,5 \right)\]and\[R\left( -2,\,3 \right)\], then the value of a is

    A) -4

    B) -12

    C) 12

    D) -6

    Correct Answer: B

    Solution :

     Given that, \[P\left( \frac{a}{3},\,4 \right)\]is the mid-point of the line segment joining the points Q (-6, 5) and R (-2, 3), which shows in the figure given below
     
    \[\therefore\] Mid-point of \[QR=P\left( \frac{-6-2}{2},\,\frac{5+3}{2} \right)\]
     =P(-4,4)
    [since, mid-point of line segment having points \[\left( {{x}_{1}},\,{{y}_{1}} \right)\] and \[\left( {{x}_{2}},\,{{y}_{2}} \right)\]
                \[\left. =\left( \frac{\left( {{x}_{1}}+{{x}_{2}} \right)}{2},\frac{\left( {{y}_{1}}+{{y}_{2}} \right)}{2} \right) \right]\]
     But mid-point \[P\left( \frac{a}{3},\,4 \right)\] is given.
    \[\therefore \,\,\,\left( \frac{a}{3},\,4 \right)=\left( -4,\,\,4 \right)\]
     On comparing the coordinates, we get
                \[\frac{a}{3}=-4\]
    \[\Rightarrow \,\,\,a=-12\]
     Hence, the required value of a is -12.
     


You need to login to perform this action.
You will be redirected in 3 sec spinner