A) 0
B) 1
C) 2
D) 3
Correct Answer: C
Solution :
| Since, A and 5 lie on the circle having centre O. OA=OB |
| \[\Rightarrow \,\,\sqrt{{{\left( 4-2 \right)}^{2}}+{{\left( 3-3 \right)}^{2}}}=\sqrt{{{\left( x-2 \right)}^{2}}+{{\left( 5-3 \right)}^{2}}}\] |
| \[\Rightarrow \,\,\,\,2=\sqrt{{{\left( x-2 \right)}^{2}}+4}\] |
| \[\Rightarrow \,\,\,4={{\left( x-2 \right)}^{2}}+4\] |
| \[\Rightarrow \,\,\,\,{{\left( x-2 \right)}^{2}}=0\] |
| \[\Rightarrow \,\,\,\,x=2\] |
You need to login to perform this action.
You will be redirected in
3 sec
