A) halved
B) doubled
C) tripled
D) quadrupled
Correct Answer: D
Solution :
| [d] \[2\pi r=4\pi \] |
| \[r=2\] |
| Area \[=\pi {{(2)}^{2}}=4\pi \] |
| When, \[2\pi r=8\pi \] |
| \[r=4\] |
| \[\therefore \] Area \[=16\,\pi \] |
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