question_answer

Is the area of the largest circle that can be drawn inside a rectangle of length a cm and breadth b cm (a > b) is ......\[c{{m}^{2}}\].

A) \[\frac{\pi {{b}^{2}}}{4}\]

B) \[\frac{\pi {{\alpha }^{2}}}{4}\]

C) \[\frac{\pi \left( {{b}^{2}}-{{a}^{2}} \right)}{4}\]

D) \[\frac{\pi {{\left( b-a \right)}^{2}}}{4}\]

Correct Answer: A

Solution :

Given, a > b Radius of the circle, \[r=\frac{b}{2}cm\] \[\therefore \]Area of circle \[=\pi {{\left( \frac{b}{2} \right)}^{2}}=\frac{\pi {{b}^{2}}}{4}c{{m}^{2}}\]