A) \[\pi {{a}^{2}}c{{m}^{2}}\]
B) \[\frac{\pi {{a}^{2}}}{2}c{{m}^{2}}\]
C) \[\frac{\pi {{a}^{2}}}{4}c{{m}^{2}}\]
D) \[2\pi {{a}^{2}}c{{m}^{2}}\]
Correct Answer: C
Solution :
Let ABCD be a square of side a. \[\therefore \] Diameter of circle = Side of square = a \[\therefore \] Radius of circle \[=\frac{a}{2}\] \[\therefore \]Area of circle \[=\pi {{\left( Radius \right)}^{2}}\] \[=\pi {{\left( \frac{a}{2} \right)}^{2}}=\frac{\pi {{a}^{2}}}{4}\] Hence, area of the circle is \[\frac{\pi {{a}^{2}}}{4}c{{m}^{2}}\]You need to login to perform this action.
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