A) \[189.97k{{m}^{2}}\]
B) \[1899.7k{{m}^{2}}\]
C) \[1709.73\text{ }k{{m}^{2}}\]
D) None of these
Correct Answer: A
Solution :
Given, sector angle, \[\theta =80{}^\circ \] and distance or radius, \[r=16.5\text{ }km\] \[\therefore \] Area of sector \[=\frac{\theta }{360{}^\circ }\times \pi {{r}^{2}}\] \[=\frac{80{}^\circ }{360{}^\circ }\times 3.14\times {{\left( 16.5 \right)}^{2}}\] \[=\frac{2\times 3.14\times 272.25}{9}\] \[=\frac{1709.73}{9}=189.97k{{m}^{2}}\] which is the required area of the sea over which the ships are warned.
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