A) \[\frac{1}{3}\pi r\,c{{m}^{2}}\]
B) \[\frac{2}{3}\pi r\,c{{m}^{2}}\]
C) \[\frac{1}{3}\pi {{r}^{2}}\,c{{m}^{2}}\]
D) \[\frac{2}{3}\pi {{r}^{2}}\,c{{m}^{2}}\]
Correct Answer: C
Solution :
Given, central angle \[\left( \theta \right)=60{}^\circ \] Area of sector \[=\frac{60{}^\circ }{360{}^\circ }\pi {{r}^{2}}\] For both the area we have to multiply by 2. Then, area \[=2\times \frac{60{}^\circ }{360{}^\circ }\times \pi {{r}^{2}}=\frac{1}{3}\pi {{r}^{2}}c{{m}^{2}}\]
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