A) \[\frac{132}{14}c{{m}^{2}}\]
B) \[\frac{36}{7}c{{m}^{2}}\]
C) \[\frac{132}{7}c{{m}^{2}}\]
D) None of these
Correct Answer: C
Solution :
We know that, area of sector of a circle \[=\frac{\theta }{360{}^\circ }\times \pi {{r}^{2}}\] Given, radius of circle, r = 6 cm and angle of sector, \[\theta =60{}^\circ \] \[\therefore \] Area of sector of a circle \[=\frac{60{}^\circ }{360{}^\circ }\times \frac{22}{7}\times {{\left( 6 \right)}^{2}}=\frac{132}{7}c{{m}^{2}}\]
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