| Arrange the following alcohols in order of |
| (i) \[{{\left( C{{H}_{3}} \right)}_{3}}C-OH\] |
| (ii) \[{{\left( C{{H}_{3}} \right)}_{2}}CH-OH\] |
| (iii) \[C{{H}_{3}}C{{H}_{2}}OH\] |
A) (iii) < (ii) < (i)
B) (ii) < (i) < (iii)
C) (i) < (ii) < (iii)
D) (iii) < (i) < (ii)
Correct Answer: C
Solution :
More the number of methyl groups (electron releasing groups) lesser will be the acidity. Hence, the reactivity towards sodium metal will be tert. < sec. < pri.
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