A) \[C{{H}_{3}}COOH\]
B) \[C{{H}_{3}}CON{{H}_{2}}\]
C) \[{{C}_{6}}{{H}_{5}}OH\]
D) \[C{{H}_{3}}C{{H}_{2}}OH\]
Correct Answer: D
Solution :
\[C{{H}_{3}}COOH\xrightarrow[-{{H}_{2}}O]{NaOH}C{{H}_{3}}COONa\] \[C{{H}_{3}}CON{{H}_{2}}\xrightarrow{NaOH}C{{H}_{3}}COONa+N{{H}_{3}}\] \[{{C}_{6}}{{H}_{5}}OH\xrightarrow{NaOH}{{C}_{6}}{{H}_{5}}ONa+{{H}_{2}}O\] But alcohols are weakly acidic even weaker than water and react with alkali metals to form alkoxides and not with alkali.
You need to login to perform this action.
You will be redirected in
3 sec
