A) 3-methylbutan-2-ol > 2-methylbutan-2-ol > pentan-1-ol
B) pentan-1-ol > 3-methylbutan-2-ol > 2 -methylbutan-2-ol
C) 2-methylbutan-2-ol > 3-methylbutan-2-ol > pentan-1-ol
D) 2-methylbutan-2-ol > pentan-1-ol > 3-methylbutan-2-ol
Correct Answer: B
Solution :
\[\underset{Pentan-1-ol}{\mathop{C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}C{{H}_{2}}C{{H}_{2}}OH}}\,\underset{3-Methylbutan-2-ol}{\mathop{>\overset{4}{\mathop{C{{H}_{3}}}}\,\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\overset{3}{\mathop{CH}}}\,-\underset{\begin{smallmatrix} | \\ OH \end{smallmatrix}}{\overset{2}{\mathop{CH}}}\,-\overset{1}{\mathop{C{{H}_{3}}}}\,>}}\,\]\[\underset{2-Methylbutan-2-ol}{\mathop{C{{H}_{3}}C{{H}_{2}}-\underset{\begin{smallmatrix} | \\ OH \end{smallmatrix}}{\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{C}}}\,-C{{H}_{3}}}}\,\] Boiling point of pri. >sec.> tert alcohol.
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