| Which of the following is the proper method to prepare n-hexane from n-propyl alcohol? |
| \[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}OH\xrightarrow{(X)}C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}Br\xrightarrow{(Y)}\] |
| \[C{{H}_{3}}{{\left( C{{H}_{2}} \right)}_{4}}C{{H}_{3}}\] |
A) (X) \[\to \]HBr, (Y) \[\to \]HCN
B) (X) \[\to \]HBr, (Y) \[\to \]Na, ether
C) (X) \[\to \]\[B{{r}_{2}}\], (Y) \[\to \]\[C{{H}_{3}}CN\]
D) (X) \[\to \]\[B{{r}_{2}}\], (Y) \[\to \]\[KMn{{O}_{4}}\]
Correct Answer: B
Solution :
\[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}OH\xrightarrow{HBr}C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}Br\xrightarrow[wurtz\,reaction]{Na/ether}\]\[\underset{n-hexane}{\mathop{C{{H}_{3}}{{\left( C{{H}_{2}} \right)}_{4}}C{{H}_{3}}}}\,\]
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