A) 8
B) 6
C) 4
D) 12
Correct Answer: A
Solution :
\[{{C}_{5}}{{H}_{12}}O={{C}_{5}}{{H}_{11}}OH\](i) | \[\underset{Pentan-1-ol}{\mathop{C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}C{{H}_{2}}OH}}\,\] | (ii) | \[\underset{Pentan-2-ol}{\mathop{C{{H}_{3}}\overset{\begin{smallmatrix} OH \\ | \end{smallmatrix}}{\mathop{CHC{{H}_{2}}}}\,C{{H}_{2}}C{{H}_{3}}}}\,\] |
(iii) | \[\underset{Pentan-3-ol}{\mathop{C{{H}_{3}}C{{H}_{2}}\overset{\begin{smallmatrix} OH \\ | \end{smallmatrix}}{\mathop{CH}}\,C{{H}_{2}}C{{H}_{3}}}}\,\] | (iv) | \[\underset{3-Methylbutan-1-ol}{\mathop{C{{H}_{3}}-\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{CH}}\,C{{H}_{2}}C{{H}_{2}}OH}}\,\] |
(v) | \[\underset{2,\text{ }2-Dimethylpropan-1-ol}{\mathop{C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{C}}}\,-C{{H}_{2}}OH}}\,\] | (vi) | \[\underset{2-Methylbutan-1-ol}{\mathop{C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ OH \end{smallmatrix}}{\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{C}}}\,-C{{H}_{2}}C{{H}_{3}}}}\,\] |
(vii) | \[\underset{3-Methylbutan-2-ol}{\mathop{C{{H}_{3}}-\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{CH}}\,-\overset{\begin{smallmatrix} OH \\ | \end{smallmatrix}}{\mathop{CH}}\,-C{{H}_{3}}}}\,\] | (viii) | \[\underset{2-Methylbutan-1-ol}{\mathop{C{{H}_{3}}C{{H}_{2}}\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{CH}}\,C{{H}_{2}}OH}}\,\] |
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