A) \[{{C}_{2}}{{H}_{5}}O{{C}_{2}}{{H}_{5}}\]and \[C{{H}_{3}}O{{C}_{2}}{{H}_{5}}\]
B) \[C{{H}_{3}}OC{{H}_{3}}\] and \[{{C}_{2}}{{H}_{5}}OC{{H}_{3}}\]
C) \[{{C}_{2}}{{H}_{5}}OH\] and \[C{{H}_{3}}OC{{H}_{3}}\]
D) \[C{{H}_{3}}OH\] and \[C{{H}_{3}}OC{{H}_{3}}\]
Correct Answer: C
Solution :
\[{{C}_{2}}\underset{(X)}{\mathop{{{H}_{5}}}}\,OH+Hl\to {{C}_{2}}{{H}_{5}}l+{{H}_{2}}O\] \[\underset{(Y)}{\mathop{C{{H}_{3}}OC{{H}_{3}}}}\,+Hl\to C{{H}_{3}}l+C{{H}_{3}}OH\]
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