A) ion prefers to combine with the smaller group in order to minimise steric hindrance
B) \[{{I}^{-}}\] ion is not reactive towards benzene
C) phenol is formed as a result of hydrolysis of iodobenzene
D) methyl alcohol formed during reaction reacts with \[{{I}^{-}}\] to form methyl iodide.
Correct Answer: A
Solution :
In the first step, ether gets protonated to form oxonium ion \[{{C}_{6}}{{H}_{5}}-\underset{\begin{smallmatrix} | \\ H \end{smallmatrix}}{\overset{+}{\mathop{O}}}\,-C{{H}_{3}}\]. I- prefers to combine with smaller group in order to reduce steric hindrance.
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