A) functional isomers
B) position isomers
C) chain isomers
D) stereo isomers.
Correct Answer: B
Solution :
\[\underset{\left(B \right)}{\mathop{C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}OH\xrightarrow[{{H}_{2}}S{{O}_{4}}]{\Delta }C{{H}_{3}}CH=C{{H}_{2}}+{{H}_{2}}O}}\,\] \[C{{H}_{3}}\underset{(B)}{\mathop{CH}}\,=C{{H}_{2}}+HCI\to \underset{(C)}{\mathop{C{{H}_{3}}}}\,\underset{\begin{smallmatrix} | \\ CI \end{smallmatrix}}{\mathop{CH}}\,-C{{H}_{3}}\] \[C{{H}_{3}}-\underset{(C)}{\overset{\begin{smallmatrix} Cl \\ | \end{smallmatrix}}{\mathop{CH}}}\,-C{{H}_{3}}+KO{{H}_{(aq.)}}\to C{{H}_{3}}-\underset{(D)}{\overset{\begin{smallmatrix} OH \\ | \end{smallmatrix}}{\mathop{CH}}}\,-C{{H}_{3}}\] [A] and [D] are position isomers.
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