A) \[{{C}_{2}}{{H}_{5}}OC{{H}_{3}}+HBr\xrightarrow{373\,K}{{C}_{2}}{{H}_{5}}OH+C{{H}_{3}}Br\]
B) \[{{C}_{2}}{{H}_{5}}O{{C}_{2}}{{H}_{5}}+\underset{Excess}{\mathop{2HI}}\,\to {{C}_{2}}{{H}_{5}}I+{{C}_{2}}{{H}_{5}}OH\]
C) \[{{C}_{2}}{{H}_{5}}O{{C}_{2}}{{H}_{5}}+HCl\xrightarrow{Cold}\left[ {{\left( {{C}_{2}}{{H}_{5}} \right)}_{2}}{{O}^{+}}H \right]C{{l}^{-}}\]
D) \[{{\left( C{{H}_{3}} \right)}_{3}}CO{{C}_{2}}{{H}_{5}}\xrightarrow{HI}{{\left( C{{H}_{3}} \right)}_{3}}CI+{{C}_{2}}{{H}_{5}}OH\]
Correct Answer: B
Solution :
\[{{C}_{2}}{{H}_{5}}-O-{{C}_{2}}{{H}_{5}}+\underset{(excess)}{\mathop{2Hl}}\,\to 2{{C}_{2}}{{H}_{5}}l+{{H}_{2}}O\]
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