A) 2-Methyl-1-propanol
B) 2-Methyl-2-propanol
C) 1-Butanol
D) 2-Butanol
Correct Answer: B
Solution :
The tertiary carbocation formed during dehydration of 2-methyl-2-propanol is most stable. \[\underset{2-Methyl-2-propanol}{\mathop{C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{C-}}}\,OH}}\,\xrightarrow[protonation]{{{H}^{+}}}C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{C-}}}\,\overset{+}{\mathop{O}}\,{{H}_{2}}\xrightarrow{-{{H}_{2}}O}\]\[\underset{\left( 3{}^\circ \,carbocation,\,most\,stable \right)}{\mathop{C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{{{C}^{+}}}}}\,}}\,\]
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