A) \[20\,N{{C}^{-1}}{{m}^{2}}\]
B) \[30\,N{{C}^{-1}}{{m}^{2}}\]
C) \[10\,N{{C}^{-1}}{{m}^{2}}\]
D) \[40\,N{{C}^{-1}}{{m}^{2}}\]
Correct Answer: A
Solution :
\[20\,N{{C}^{-1}}\,{{m}^{2}}\] Here, \[E=2\times {{10}^{3}}\,N{{C}^{-1}}\]is along + X-axis Surface area, \[S={{\left( 10\,cm \right)}^{2}}\] \[={{10}^{2}}\times {{10}^{-4}}{{m}^{2}}={{10}^{-2}}{{m}^{2}}\] When plane is parallel to y-z plane, \[\theta =0{}^\circ \] So, \[\phi =ES\,\cos \theta =2\times {{10}^{3}}\times {{10}^{-2}}\cos 0{}^\circ \] \[=20\,N{{C}^{-1}}{{m}^{2}}\]
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