A) A
B) B
C) C
D) A and B
Correct Answer: C
Solution :
(c) C Particles A and B have negative charges because they are being deflected towards the positive plate of the electrostatic field. Particle C has positive charge because it is being deflected towards the negative plate. \[\therefore \]Deflection of charged particle in time tin y-direction \[h=0\times t+\frac{1}{2}a{{t}^{2}}=\frac{1}{2}\frac{qE}{m}{{t}^{2}}\] i.e., \[h\propto \frac{q}{m}\] As the particle C suffers maximum deflection in y-direction, so it has highest charge of mass (q/m) ratio.
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