A) \[5.6\times {{10}^{11}}N/C\]
B) \[1.44\text{ }\times {{10}^{11}}\text{ }N/C\]
C) \[2.828\text{ }\times {{10}^{11}}\text{ }N/C\]
D) zero
Correct Answer: B
Solution :
(b) \[1.44\text{ }\times {{10}^{11}}\text{ }N/C\] \[E=9\times {{10}^{9}}\times \frac{{{q}^{2}}}{{{r}^{2}}}\] \[=9\times {{10}^{9}}\times \frac{{{q}^{2}}}{{{r}^{2}}}\] \[=9\times {{10}^{9}}\times \frac{1.6\times {{10}^{-19}}}{\left( 1\times {{10}^{-10}} \right)}=1.44\times {{10}^{11}}N/C\]
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