A) \[\left[ {{M}^{-1}}{{L}^{1}}{{T}^{3}}{{A}^{-1}} \right]\]
B) \[\left[ M{{L}^{-1}}{{T}^{-3}}{{A}^{1}} \right]\]
C) \[\left[ {{M}^{1}}{{L}^{1}}{{T}^{-3}}{{A}^{-1}} \right]\]
D) \[\left[ {{M}^{1}}{{L}^{2}}{{T}^{1}}{{A}^{1}} \right]\]
Correct Answer: C
Solution :
(c) \[\left[ {{M}^{1}}{{L}^{1}}{{T}^{-3}}{{A}^{-1}} \right]\] Since. \[E=\frac{F}{q},\,\left( E \right)=\frac{\left[ {{M}^{1}}{{L}^{1}}{{T}^{-2}} \right]}{\left[ AT \right]}=\left[ {{M}^{1}}{{L}^{1}}{{T}^{-3}}{{A}^{-1}} \right]\]
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