A) \[1.6\times {{10}^{19}}\]
B) \[6.25\times {{10}^{9}}\]
C) \[6.25\times {{10}^{9}}\]
D) \[6.25\times {{10}^{28}}\]
Correct Answer: B
Solution :
(b) \[6.25\times {{10}^{9}}\] Given, \[q=1\,nC=1\times 1\times {{10}^{-9}}C\] and \[e=1.6\times {{10}^{-19}}\] From the property of quantisation charge, \[q=ne\] \[\Rightarrow \,n=\frac{q}{e}=\frac{1\times {{10}^{-9}}}{1.6\times {{10}^{-19}}}\] \[=0.625\times {{10}^{-9}}\times {{10}^{19}}\times {{10}^{19}}=6.25\times {{10}^{9}}\]
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