A) \[\frac{\sigma }{2{{\varepsilon }_{0}}}\]downwards
B) \[\frac{\sigma }{2{{\varepsilon }_{0}}}\]upwards
C) \[\frac{\sigma }{2{{\varepsilon }_{0}}}\]downwards
D) \[\frac{\sigma }{2{{\varepsilon }_{0}}}\]upwards
Correct Answer: A
Solution :
\[\frac{\sigma }{2{{\varepsilon }_{0}}}\]downwards Using Gauss law, electric field due to an infinite plane sheet can be obtained. \[\therefore \,\,2E\,\,dS\,\,=\sigma \frac{dS}{{{\varepsilon }_{0}}}\] Or \[E=\frac{\sigma }{2{{\varepsilon }_{0}}}\] Hence, electric field is \[\frac{\sigma }{2{{\varepsilon }_{0}}}\] downwards.
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