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12th Class Physics Electric Charges and Fields Question Bank MCQ - Electric Charges and Fields

  • question_answer
    The electric field components in the given figure are \[{{E}_{x}}=\alpha {{x}^{1/2}}\], \[{{E}_{y}}={{E}_{z}}=0\] which \[\alpha =800\,N{{C}^{-1}}{{m}^{-1/2}}\]. The charge within the cube, if net flux through the cube is \[1.05\,N{{m}^{2}}{{C}^{-1}}\]is (assume, a =0.1 m):

    A) \[9.27\times {{10}^{-12}}C\]    

    B) \[9.27\times {{10}^{12}}C\]

    C) \[6.97\times {{10}^{-12}}C\]

    D) \[6.97\times {{10}^{12}}C\]

    Correct Answer: A

    Solution :

    \[9.27\times {{10}^{-12}}C\] By Gauss's law,\[\phi =\frac{q}{{{\varepsilon }_{0}}}\] Or \[q=\phi {{\varepsilon }_{0}}=1.05\times 8.854\times {{10}^{-12}}C\] \[=9.30\times {{10}^{-12}}C\]


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