A) 2F
B) F/2
C) F/4
D) (d) F/8
Correct Answer: D
Solution :
F/8 Let charge q is placed at a distance rfrom the dipole. Electric field due to dipole at axial point, \[E=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{2p}{{{r}^{3}}}\] Force on charge \[q,F=qE\] \[=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{2pq}{{{\left( 2r \right)}^{3}}}\] When we double the distance \[F'=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{2pq}{{{\left( 2r \right)}^{3}}}\] \[F'=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{2pq}{{{r}^{3}}}\left( \frac{1}{8} \right)\] \[F'=\frac{F}{8}\]
You need to login to perform this action.
You will be redirected in
3 sec
