A) 1 : 2
B) 2 : 1
C) 1 : 4
D) 4 : 1
Correct Answer: B
Solution :
(b) 2 : 1 Electric field due to dipole on its axis, \[{{E}_{1}}=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{2p}{{{r}^{3}}}\] Electric field due to dipole on its perpendicular bisector, \[{{E}_{2}}=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{p}{{{r}^{3}}}\] \[\frac{{{E}_{1}}}{{{E}_{2}}}=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{2p}{{{r}^{3}}}\times 4\pi {{\varepsilon }_{0}}\frac{{{r}^{3}}}{p}\] \[\frac{{{E}_{1}}}{{{E}_{2}}}=\frac{2}{1}\] or \[2\,\,:\,\,1\] 0.
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