A) E
B) \[\frac{E}{2}\]
C) \[\frac{E}{4}\]
D) \[\frac{3E}{2}\]
Correct Answer: B
Solution :
(b) \[\frac{E}{2}\] We know that, \[V=\frac{ER}{R+r}\] \[=\frac{ER}{R+R}\] \[[\because \,R=r]\] \[=\frac{ER}{2R}=\frac{E}{2}\]You need to login to perform this action.
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