JEE Main & Advanced Mathematics Applications of Derivatives Question Bank Maxima and Minima

  • question_answer
    The adjacent sides of a rectangle with given perimeter as 100 cm and enclosing maximum area are  [MP PET 1993]

    A)            10 cm and 40 cm

    B)            20 cm and 30 cm

    C)             25 cm and 25 cm

    D)   15 cm and 35 cm

    Correct Answer: C

    Solution :

               \[2x+2y=100\Rightarrow x+y=50\]                                ?..(i)            Let area of rectangle is A; \[\therefore A=xy\Rightarrow y=\frac{A}{x}\]            Put in (i), we have \[x+\frac{A}{x}=50\Rightarrow A=50x-{{x}^{2}}\]            Þ \[\frac{dA}{dx}=50-2x\]            For maximum area \[\frac{dA}{dx}=0\]            \[\therefore 50-2x=0\Rightarrow x=25\]and \[y=25\]             Hence adjacent sides are 25 and 25 cm.


You need to login to perform this action.
You will be redirected in 3 sec spinner