A) \[\frac{\pi }{3}\]
B) \[\frac{\pi }{4}\]
C) \[\frac{\pi }{6}\]
D) \[\frac{\pi }{2}\]
Correct Answer: D
Solution :
Let a and b are given, then area \[A=\frac{1}{2}ab\sin C\] \[\Rightarrow \frac{dA}{dC}=\frac{1}{2}ab\cos C\] Hence A is maximum, when \[\frac{dA}{dC}=0\Rightarrow C=90{}^\circ \].
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