A) Increase
B) Decrease
C) Wavelength does not depend on the kinetic energy
D) None of the above
Correct Answer: B
Solution :
\[\lambda =\frac{h}{p}=\frac{h}{\sqrt{2mE}};\ \ \therefore \ \lambda \propto \frac{1}{\sqrt{E}}\] (h and m = constant)You need to login to perform this action.
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