A) 100 Å
B) 123 Å
C) 1.23 Å
D) 0.123 Å
Correct Answer: C
Solution :
\[\lambda =\frac{h}{\sqrt{2mQV}}=\frac{6.6\times {{10}^{-34}}}{\sqrt{2\times 9.1\times {{10}^{-31}}\times 1.6\times {{10}^{-19}}\times 100}}\] \[=1.23\,{\AA}\]
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