A) 0.168 eV
B) 16.8 eV
C) 1.68 eV
D) 2.5 eV
Correct Answer: B
Solution :
\[=5.469\times {{10}^{-10}}m=5.47{\AA}\] \[\lambda =\frac{h}{|p|}=\frac{h}{|I|}\]\[=2.65\times {{10}^{-18}}J\] \[=16.8\,eV\]
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