A) 2 : 1
B) 1 : 2
C) 4 : 1
D) 1 : 4
Correct Answer: A
Solution :
\[\lambda =\frac{h}{\sqrt{2mE}}\Rightarrow \lambda \propto \frac{1}{\sqrt{m}}\Rightarrow \frac{{{\lambda }_{p}}}{{{\lambda }_{\alpha }}}=\sqrt{\frac{{{m}_{\alpha }}}{{{m}_{p}}}}=\frac{2}{1}\]
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