JEE Main & Advanced Physics Photo Electric Effect, X- Rays & Matter Waves Question Bank Matter Waves

  • question_answer
    An electron of mass m when accelerated through a potential difference V has de-Broglie wavelength \[\lambda \]. The de-Broglie wavelength associated with a proton of mass M accelerated through the same potential difference will be [CBSE PMT 1995; EAMCET 2001; J & K CET 2004]

    A)            \[\lambda \frac{m}{M}\]

    B)            \[\lambda \sqrt{\frac{m}{M}}\]

    C)            \[\lambda \frac{M}{m}\]

    D)            \[\lambda \sqrt{\frac{M}{m}}\]

    Correct Answer: B

    Solution :

               \[\lambda =\frac{h}{\sqrt{2mE}}\] Þ \[\lambda \propto \frac{1}{\sqrt{m}}\]                          (E = same)


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