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8th Class Mathematics Related to Competitive Exam Question Bank Mathematical Operations

  • question_answer
    If the given interchanges namely: signs + and \[~15-5\div 5\times 20+10=6\] and numbers 2 and 4 are made in sign and numbers, which one of the following four equations would be correct?

    A)  \[8\div 10-3+5\times 6=8\]               

    B)  \[6\times 2+3\div 12-3==15\]

    C)  \[3\div 7-5\times 10+3=10\]             

    D)  \[=15\times 5+5-20+10\]

    Correct Answer: D

    Solution :

        Interchanging (+ and \[\div \]) and (2 and 4), we get: (a) \[\Rightarrow \]or \[\Delta \], which is false (b) \[\Rightarrow \]or \[p\Delta q\] which is false. (c) \[\Rightarrow \] or \[3+5=16;\] which is false. (d) \[7+9=64;\] or \[10+12=121,\], which is true.


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