A) Increase by 19%
B) Decrease by 19%
C) Increase by 11%
D) Decrease by 21%
Correct Answer: C
Solution :
\[T=2\pi \sqrt{\frac{I}{M{{B}_{H}}}}\Rightarrow T\propto \frac{1}{\sqrt{M}}\Rightarrow \frac{{{T}_{1}}}{{{T}_{2}}}=\sqrt{\frac{{{M}_{2}}}{{{M}_{1}}}}\] If M1 =100 than M2 (100 ? 19) = 81 So \[\frac{{{T}_{1}}}{{{T}_{2}}}=\sqrt{\frac{81}{100}}=\frac{9}{10}\Rightarrow {{T}_{2}}=\frac{10}{9}{{T}_{1}}=1.11\,{{T}_{1}}\] \[\Rightarrow \]Time period increases by 11%
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