A) 0.23 Joule/Tesla
B) 0.40 Joule/Tesla
C) 0.80Joule/Tesla
D) Zero
Correct Answer: B
Solution :
\[\tau =M{{B}_{H}}\sin \theta \Rightarrow 0.032=M\times 0.16\times \sin {{30}^{o}}\] \[\Rightarrow M=0.4J/tesla\]
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