A) \[\theta =0{}^\circ \]
B) \[\theta =45{}^\circ \]
C) \[\theta =60{}^\circ \]
D) \[\theta =90{}^\circ \]
Correct Answer: A
Solution :
\[\tau =M{{B}_{H}}\sin \theta \] or \[\frac{d\tau }{d\theta }=M{{B}_{H}}\cos \theta \] This will be maximum. when \[\theta ={{0}^{o.}}\]
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