A) \[{{2}^{-3}}\]
B) \[{{2}^{-1/3}}\]
C) \[{{2}^{3}}\]
D) \[{{2}^{1/3}}\]
Correct Answer: D
Solution :
\[{{B}_{1}}=\frac{2M}{{{x}^{3}}}\ and\ {{B}_{2}}=\frac{M}{{{y}^{3}}}\] As \[{{B}_{1}}={{B}_{2}}\] Hence \[\]\[\frac{2M}{{{x}^{3}}}=\frac{M}{{{y}^{3}}}\text{or}\frac{{{x}^{3}}}{{{y}^{3}}}=2\ \text{or}\ \frac{x}{y}={{2}^{1/3}}\]
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