A) 9.6
B) 2.4
C) \[9.6\times {{10}^{3}}\]
D) \[2.4\times {{10}^{3}}\]
Correct Answer: A
Solution :
1000 ml of \[C{{H}_{3}}OH\] requires methanol = 32 g. 150 ml of 2 M \[C{{H}_{3}}OH\] requires methanol \[=\frac{32}{1000}\times 150\times 2=9.6\,g\].
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