JEE Main & Advanced Chemistry Solutions / विलयन Question Bank Lowering of vapour pressure

  • question_answer
    60 gm of Urea (Mol. wt 60) was dissolved in 9.9 moles, of water. If the vapour pressure of pure water is \[{{P}_{o}}\], the vapour pressure of solution is                      [DCE 2000]

    A)                 0.10 \[{{P}_{o}}\]               

    B)                 1.10 \[{{P}_{o}}\]

    C)                 0.90 \[{{P}_{o}}\]               

    D)                 0.99 \[{{P}_{o}}\]

    Correct Answer: C

    Solution :

             \[\frac{{{P}^{0}}-{{P}_{s}}}{{{P}^{0}}}=\frac{n}{N}\Rightarrow \frac{{{P}^{0}}-{{P}_{s}}}{{{P}^{0}}}=\frac{1}{9.9}\Rightarrow 9.9{{P}^{0}}-9.9{{P}_{s}}={{P}^{0}}\]                         \[8.9{{P}^{0}}=9.9{{P}_{s}}\Rightarrow {{P}_{s}}=\frac{8.9}{9.9}{{P}^{0}}\approx 0.90{{P}^{0}}\]


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