A) 1.25 mm Hg
B) 0.125 mm Hg
C) 1.15 mm Hg
D) 00.12 mm Hg
Correct Answer: B
Solution :
Given molecular mass of sucrose = 342 Moles of sucrose \[=\frac{100}{342}=0.292\] mole Moles of water \[N=\frac{1000}{18}=55.5\] moles and Vapour pressure of pure water \[{{P}^{0}}=23.8\] mm Hg According to Raoult?s law \[\frac{\Delta P}{{{P}^{0}}}=\frac{n}{n+N}\Rightarrow \frac{\Delta P}{23.8}=\frac{0.292}{0.292+55.5}\] \[\Delta P=\frac{23.8\times 0.292}{55.792}=0.125\]mm Hg.You need to login to perform this action.
You will be redirected in
3 sec