A) 1 M \[C{{}_{12}}{{H}_{22}}{{O}_{11}}\]
B) 1 M \[C{{H}_{3}}COOH\]
C) 1 M \[NaC{{l}_{2}}\]
D) 1 M \[NaCl\]
Correct Answer: A
Solution :
Sucrose will give minimum value of \[\Delta P\]. \[\Delta P={{P}^{0}}-{{P}_{s}}\] \[{{P}_{s}}={{P}^{0}}-\Delta P\]is maximum.
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