JEE Main & Advanced Chemistry Solutions / विलयन Question Bank Lowering of vapour pressure

  • question_answer
    Vapour pressure of \[CC{{l}_{4}}\] at \[{{25}^{o}}C\] is \[143mm\] of \[Hg\,0.5\,gm\] of a non-volatile solute (mol. wt. = 65) is dissolved in \[100\,ml\,CC{{l}_{4}}\]. Find the vapour pressure of the solution (Density of \[CC{{l}_{4}}=1.58\,g/c{{m}^{2}}\])     [CBSE PMT 1998]

    A)                 \[141.43\,mm\]     

    B)                 \[94.39\,mm\]

    C)                 \[199.34\,mm\]     

    D)                 \[143.99\,mm\]

    Correct Answer: A

    Solution :

             \[\frac{{{P}^{0}}-Ps}{{{P}^{0}}}=\frac{w\times M}{m\,\,W}\]\[=143-\frac{0.5\times 154}{65\times 158}\times 143\]                              \[=143-1.03=141.97\,mm\].


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