A) 1/2
B) : \[-1\]
C) \[\frac{-1}{3}\]
D) -3
Correct Answer: B
Solution :
(b): \[lo{{g}_{100}}0.01\] \[\frac{1}{2}lo{{g}_{10}}{{(10)}^{-2}}\] \[=\frac{-2}{2}lo{{g}_{10}}10\] =\[-1\]
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