A) 4
B) 3
C) 2
D) 1
Correct Answer: D
Solution :
(d): \[{{\left[ lo{{g}_{10}}(51o{{g}_{10}}100) \right]}^{2}}={{\left[ lo{{g}_{10}}(5lo{{g}_{10}}{{10}^{2}}) \right]}^{2}}\text{ }\] =\[{{\left[ lo{{g}_{10}}(10lo{{g}_{10}}10) \right]}^{2}}\] \[={{\left[ {{\log }_{10}}10 \right]}^{2}}(\therefore lo{{g}_{10}}10=1)\] \[={{1}^{2}}=1\]
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