A) 9
B) 8
C) 3
D) 2
Correct Answer: B
Solution :
(b): \[{{2}^{lo{{g}_{3}}^{9}}}+{{25}^{lo{{g}_{9}}^{3}}}={{8}^{{{\log }_{x}}^{9}}}\] \[\Rightarrow {{2}^{log}}{{^{_{3}3}}^{^{2}}}+{{25}^{{{\log }_{{{3}^{2}}}}3}}={{8}^{{{\log }_{x}}9}}\] \[\Rightarrow {{2}^{2}}+{{25}^{1/2}}={{8}^{{{\log }_{x}}9}}\] \[\Rightarrow 9={{8}^{{{\log }_{x}}9}}\] \[\Rightarrow {{\log }_{x}}9={{\log }_{8}}9\] \[\Rightarrow x=8\].
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