A) \[lo{{g}_{2}}6\]
B) \[lo{{g}_{2}}5\]
C) \[lo{{g}_{10}}6\]
D) \[lo{{g}_{10}}30\]
Correct Answer: C
Solution :
(c): \[\frac{{{\log }_{5}}6}{{{\log }_{5}}2+1}=\frac{{{\log }_{5}}6}{{{\log }_{5}}2+{{\log }_{5}}5}=\frac{{{\log }_{5}}6}{{{\log }_{5}}(2\times 5)}\] \[=\frac{{{\log }_{5}}6}{{{\log }_{5}}10}={{\log }_{10}}6.\]
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